(\u5141\u8bb8\u6709\u524d\u5bfc0)<\/span><\/strong>\u3002<\/p>\n 2. \u6784\u6210\u5b83\u7684\u6bcf\u4e2a\u6570\u5b57\u90fd\u5728\u7ed9\u5b9a\u7684\u6570\u5b57\u96c6\u5408S\u4e2d\u3002<\/p>\n
3. \u5b83\u524dn\u4f4d\u4e4b\u548c\u4e0e\u540en\u4f4d\u4e4b\u548c\u76f8\u7b49\u6216\u8005\u5b83\u5947\u6570\u4f4d\u4e4b\u548c\u4e0e\u5076\u6570\u4f4d\u4e4b\u548c\u76f8\u7b49<\/p>\n
\u4f8b\u5982\u5bf9\u4e8en=2,S={1,2}\uff0c\u5408\u6cd5\u7684\u597d\u6570\u5b57\u67091111,1122,1212,1221,2112,2121,2211,2222\u8fd9\u68378\u79cd\u3002<\/p>\n
\u5df2\u77e5n\uff0c\u6c42\u5408\u6cd5\u7684\u597d\u6570\u5b57\u7684\u4e2a\u6570mod 999983\u3002<\/p>\n
\u3010\u8f93\u5165格\u5f0f\u3011<\/p>\n
\u7b2c\u4e00\u884c\u4e00\u4e2a\u6570n\u3002 <\/p>\n
\u63a5\u4e0b\u6765\u4e00\u4e2a\u957f\u5ea6\u4e0d\u8d85\u8fc710\u7684\u5b57\u7b26\u4e32\uff0c\u8868\u793a\u7ed9\u5b9a\u7684\u6570\u5b57\u96c6\u5408\u3002<\/p>\n
\u3010\u8f93\u51fa格\u5f0f\u3011<\/p>\n
\u4e00\u884c\u4e00\u4e2a\u6570\u5b57\u8868\u793a\u5408\u6cd5\u7684\u597d\u6570\u5b57\u7684\u4e2a\u6570mod 999983\u3002<\/p>\n
\u3010\u6837\u4f8b\u8f93\u5165\u3011<\/p>\n
2<\/p>\n
0987654321<\/p>\n
\u3010\u6837\u4f8b\u8f93\u51fa\u3011<\/p>\n
1240<\/p>\n
\u3010\u6570\u636e\u89c4\u6a21\u3011<\/p>\n
\u5bf9\u4e8e20%\u7684\u6570\u636e\uff0cn\u22647\u3002<\/p>\n
\u5bf9\u4e8e100%\u7684.\u636e,n\u22641000,|S|\u226410\u3002<\/p>\n
\n<\/p>\n
\n<\/p>\n
\u8fd9\u9898\u96be\u70b9\u5728\u6c42\u524dn\u4f4d\u4e4b\u548c\u4e0e\u540en\u4f4d\u4e4b\u548c\u76f8\u7b49\u4e0e\u5b83\u5947\u6570\u4f4d\u4e4b\u548c\u4e0e\u5076\u6570\u4f4d\u4e4b\u548c\u76f8\u7b49\u7684\u4ea4\u96c6<\/p>\n
\u2026\u2026<\/p>\n
\u8bb0\u5f97\u7b2c\u4e00\u4e2a\u6570\u4e00\u5b9a\u8981\uff08long long ) c++\u4e2d\u5bf9 3000\u8fd9\u6837\u7684\u5e38\u91cf\u90fd\u662f\u7b97int\u7684\uff0c\u800c\u7b49\u53f7\u4f18\u5148\u7ea7\u6700\u4f4e<\/p>\n
\n<\/p>\n
\u53e6\u5916\u672c\u9898\u662f\u4e58\u6cd5\u539f\u7406+\u52a0\u6cd5\u539f\u7406<\/p>\n
\n<\/p>\n
\u5148\u7528\u4e58\u6cd5\u539f\u7406 \u6c42\u51fa A=x a=y B=y b=x \u7684\u65b9\u6848\u6570 \u8bb0\u5f97%F<\/p>\n
\u7136\u540e\u5c06\u6240\u6709\u7684\u60c5\u51b5\u76f8\u52a0++<\/p>\n
\n<\/p>\n
#include<cstdio>\n#include<cstring>\n#include<cstdlib>\n#include<cmath>\n#include<cctype>\n#include<functional>\n#include<algorithm>\n#include<iostream>\nusing namespace std;\n#define F (999983)\n#define MAXN (1000+10)\n#define MAXM (10000+10)\nint n,m;\nchar s[100];\nint a[100],siz=0;\nint f[MAXN][MAXM];\nint main()\n{\n freopen("num.in","r",stdin);\n freopen("num.out","w",stdout);\n scanf("%d",&n);\n scanf("%s",s);\n memset(f,0,sizeof(f));\n for (int i=0;i<strlen(s);i++)\n a[++siz]=s[i]-'0';\n\n\/\/ for (int i=1;i<=siz;i++) cout<<a[i]<<' ';\n sort(a+1,a+1+siz);\n for (int i=1;i<=siz;i++)\n {\n f[1][a[i]]=1;\n\/\/ cout<<a[i]<<' ';\n }\n f[0][0]=1;\n\n for (int i=2;i<=n;i++)\n for (int j=i*a[1];j<=i*a[siz];j++)\n {\n \/* if (j==18)\n {\n cout<<'s';\n }\n *\/ for (int k=1;k<=siz;k++)\n if (j-a[k]>=0)\n f[i][j]=(f[i][j]+(f[i-1][j-a[k]])%F)%F;\n }\n long long ans=0;\n for (int j=0;j<=n*a[siz];j++)\n {\n \/\/ if (f[n][j]>0) cout<<j<<' '<<f[n][j]<<endl;\n ans=ans+(long long)(f[n][j])*(long long)(f[n][j]);\n \tans%=F;\n\t}\n\n\n \/\/ cout<<(2*ans)%F<<endl;\n\n \t\/*\u73b0\u5728\u5f00\u59cb\u51e0\u7b97\u76f8\u540c\u7684\u60c5\u51b5\n \tA \u524d\u5947 B \u524d\u5076 a \u540e\u5947 b \u540e\u5076\n\n\t \u663e\u7136 A+a=B+b A+a=B+b ->A=b&&sa=B\n\n\t \u5219\u7b54\u6848\u4e3a\n\n\t \u2211\uff08a*A*b*B) \u8fd94\u4e2a\u6570\u4e3a(\u6b64\u5904a,A,b,B\u6307\u5f53\u5b83\u4eec\u6b63\u597d\u7b49\u4e8e\u8fd9\u4e2a\u503c\u7684\u65b9\u6848\u6570\n\t \u2211 \uff08a^2*A^2)\n\t \u2211 (f[n\/2.i]^2*f[n\/2+n%2,i])\n\n\t*\/\n\/\/\tcout<<ans<<endl;\n\tlong long tmpA=0;\n\tfor (int i=(n\/2)*a[1];i<=(n\/2)*a[siz];i++)\n\t tmpA=(tmpA+(long long)f[n\/2][i]*f[n\/2][i])%F;\n\n\tlong long tmpB=0;\n\tfor (int i=(n\/2+n%2)*a[1];i<=(n\/2+n%2)*a[siz];i++)\n\t tmpB=(tmpB+(long long)f[n\/2+n%2][i]*f[n\/2+n%2][i])%F;\n\n\/\/\tcout<<tmpA<<' '<<tmpB;\n\n\/\/\t cout<<tmpA*tmpB<<endl;\n\n\tans=(ans*2)%F;\n\/\/\tcout<<ans<<endl;\n\n {\n\/\/\t\tcout<<ans<<' '<<tmpA*tmpB;\n\t}\n\n\n\n\n\tans=(ans-tmpA*tmpB+F*((tmpA*tmpB)\/F)+F)%F;\n\n\n cout<<ans<<endl;\n\n\n\n \/\/ while(1);\n return 0;\n}\n<\/pre>\n<\/p>\n\n<\/p>\n
\n<\/p>\n
<\/p>\n","protected":false},"excerpt":{"rendered":"
\u6570\u5b57 (num.c\/cpp\/pas) \u3010\u95ee\u9898\u63cf\u8ff0\u3011 \u4e00\u4e2a\u6570\u5b57\u88ab\u79f0\u4e3a\u597d\u6570\u5b57 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_coblocks_attr":"","_coblocks_dimensions":"","_coblocks_responsive_height":"","_coblocks_accordion_ie_support":"","footnotes":""},"categories":[3],"tags":[111],"class_list":["post-244","post","type-post","status-publish","format-standard","hentry","category-defaultcategory","tag-combinatorial_mathematics"],"yoast_head":"\n
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