{"id":289,"date":"2012-11-28T15:38:00","date_gmt":"2012-11-28T07:38:00","guid":{"rendered":"http:\/\/nike0good.jp1.rpvhost.net\/194"},"modified":"2012-11-28T15:38:00","modified_gmt":"2012-11-28T07:38:00","slug":"and_hdu_1542_rectangular_area","status":"publish","type":"post","link":"https:\/\/nike0good.com\/?p=289","title":{"rendered":"HDU 1542(\u77e9\u5f62\u9762\u79ef\u5e76\uff09"},"content":{"rendered":"

\nAtlantis<\/h1>\n
\nProblem Description<\/div>\n
\n\u5df2\u77e5Atlantis\u7684\u5730\u56fe\u7531\u8bb8\u591a\u77e9\u5f62\u6784\u6210\uff0c\u6c42\u5b83\u4eec\u7684\u9762\u79ef\u5e76\u3002\n<\/div>\n
\n <\/div>\n


<\/p>\n

\nInput<\/div>\n
\n\u9898\u76ee\u6709\u591a\u7ec4\u6570\u636e\uff0c\u6bcf\u7ec4\u6570\u636e\u7684\u5f00\u5934\u6709\u4e00\u4e2a\u6574\u6570n(1<=n<=100)\uff0c\u8868\u793a\u5730\u56fe\u6570\uff0c\u63a5\u4e0b\u6765n\u884c,\u6bcf\u884c4\u4e2a\u5c0f\u6570 x1;y1;x2;y2 (0<=x1<x2<=100000;0<=y1<y2<=100000), \u8868\u793a\u8fd9\u5f20\u5730\u56fe\u5de6\u4e0a\u89d2\u5750\u6807 (x1; y1)\u548c\u53f3\u4e0a\u89d2\u5750\u6807 (x2;y2).<\/div>\n
\n\u6570\u636e\u4ee50\u7ed3\u675f<\/div>\n
\n <\/div>\n


<\/p>\n

\nOutput<\/div>\n
\n\u5bf9\u4e8e\u6bcf\u7ec4\u6570\u636e\uff0c\u4f60\u9700\u8981\u8f93\u51fa\u4e00\u884c \u201cTest case #k\u201d,k\u8868\u793a\u7b2ck\u7ec4\u6570\u636e(\u4ece1\u5f00\u59cb).\u7b2c\u4e8c\u884c\u4e3a\u201cTotal explored area: a\u201d,a\u4e3a\u9762\u79ef\u5e76\uff08\u4fdd\u75592\u4f4d\u5c0f\u6570\uff09\uff0c\n<\/div>\n
\n\u6bcf\u7ec4\u6570\u636e\u540e\uff0c\u8bf7\u8f93\u51fa\u4e00\u4e2a\u56de\u8f66\u3002<\/div>\n
\n <\/div>\n


<\/p>\n

\nSample Input<\/div>\n
\n
2\n10 10 20 20\n15 15 25 25.5\n0<\/div><\/pre>\n<\/div>\n
\n <\/div>\n

<\/p>\n
\nSample Output<\/div>\n
\n
Test case #1\nTotal explored area: 180.00 <\/div><\/pre>\n<\/div>\n
\n <\/div>\n
\u77e9\u5f62\u9762\u79ef\u5e76\u5165\u95e8\u9898\uff0c<\/span><\/p>\n
\u9996\u5148\u628a\u76f4\u7ebf\u62c6\u6210\u4e0a\u8fb9\u548c\u4e0b\u8fb9\uff0c\u6309\u9ad8\u5ea6\u6392\u5e8f\uff0c<\/span><\/p>\n
\u6a2a\u5750\u6807\u79bb\u6563\u5316\uff0c\u5efa\u7acb\u7ebf\u6bb5\u6811\u3002<\/span><\/p>\n
cnt[]\u8868\u793a\u67d0\u6761\u7ebf\u6bb5\u88ab\u8986\u76d6\u7684\u6b21\u6570\uff0csum[]\u8868\u793a\u4e00\u6761\u7ebf\u6bb5\u88ab\u8986\u76d6\u7684\u957f\u5ea6<\/span><\/p>\n
\u6211\u4eec\u5728\u8ba1\u7b97cnt[]\u65f6,\u6ca1\u4fee\u65391\u4e2acnt[],\u5c31\u7528pushup\u628asum[]\u66f4\u65b0\uff0c\u5f97\u5230\u7a0b\u5e8f1\uff1a<\/span><\/p>\n

\n<\/span><\/p>\n

\n<\/span><\/p>\n
<\/span><\/p>\n
#include<cstdio>\n#include<cstring>\n#include<cstdlib>\n#include<cmath>\n#include<cctype>\n#include<iostream>\n#include<functional>\n#include<algorithm>\n#include<map>\nusing namespace std;\n#define MAXN (2000+10)\n#define MAXT (1000*2*10)\n#define Lson (x<<1)\n#define Rson ((x<<1)^1)\nint tt,n,size;\ndouble x[MAXN];\nstruct SegMent\n{\n    double x1,x2,h;\n    int type;\n    SegMent(){}\n    SegMent(double _x1,double _x2,double _h,int _type):x1(_x1),x2(_x2),h(_h),type(_type){}\n    friend bool operator<(const SegMent a,const SegMent b){return a.h<b.h;    }\n}a[MAXN];\nmap<double , int>  hpos;\ndouble len[MAXT];\nstruct SegMentTree\n{\n    int n,M,cnt[MAXT];\n    double sum[MAXT];\n    int mark[MAXT];\n    void fillchar(int _n)\n    {\n        n=_n;\n        memset(cnt,0,sizeof(cnt));\n        memset(sum,0,sizeof(sum));\n        memset(mark,0,sizeof(mark));\n        M=1;while (M-2<n) M<<=1;\n        x[0]=0;memset(len,0.0,sizeof(len));\n        for (int i=M+1;i<=M+size;i++) len[i]=x[i-M]-x[i-M-1];\n        for (int i=M-1;i>0;i--) len[i]=len[i<<1]+len[(i<<1)^1];\n    }\n    void pushdown(int x)\n    {\n        if (x>>1) pushdown(x>>1);\n        if (mark[x])\n        {\n            mark[Lson]+=mark[x];\n            cnt[Lson]+=mark[x];\n            mark[Rson]+=mark[x];\n            cnt[Rson]+=mark[x];\n            mark[x]=0;\n        }\n    }\n    void pushup(int x)\n    {\n    \/\/    pushdown(x);cout<<mark[5];\n    \/\/    cout<<x<<' ';\n\n        sum[x]=cnt[x]?len[x]:(x>=M?0:sum[Lson]+sum[Rson]);\n    }\n    void update(int x)\n    {\n        for (;x;x>>=1)\n        {\n        \/\/    cout<<"push "<<x<<endl;\n            pushup(x);\n        }\n    }\n\n    void insert(int l,int r,int c)\n    {\n        int ll=l-1+M,rr=r+1+M;\n        for (l=l-1+M,r=r+1+M,pushdown(l>>1),pushdown(r>>1);l^r^1;l>>=1,r>>=1)\n        {\n            if (~l&1) {cnt[l+1]+=c;update(l+1);\/*mark[l+1]+=c;*\/} \/*\u6539\u53d8sum\u7684\u503c *\/\n            if (r&1) {cnt[r-1]+=c;update(r-1);\/* mark[r-1]+=c;*\/}\n        }\n\/\/        update(ll);update(rr); \/\/\u5411\u4e0a\u4f20\u9012\n    }\n    void print()\n    {\n        cout<<"cnt ";\n        for (int i=1;i<=M*2;i++) if (cnt[i]) cout<<i<<':'<<cnt[i]<<' ';\n        cout<<endl;\n        cout<<"sum ";\n        for (int i=1;i<=M*2;i++) if (sum[i]) cout<<i<<':'<<sum[i]<<' ';\n        cout<<endl;\n        cout<<"Mark ";\n        for (int i=1;i<=M*2;i++) if (mark[i]) cout<<i<<':'<<mark[i]<<' ';\n        cout<<endl;\n    }\n}t;\n\nint main()\n{\n\/\/    freopen("Hdu1542.in","r",stdin);\n    tt=0;\n    while (scanf("%d",&n)!=EOF)\n    {\n        tt++;\n        if (!n) break;\n        for (int i=1;i<=2*n;i+=2)\n        {\n            scanf("%lf%lf%lf%lf",&a[i].x1,&a[i].h,&a[i].x2,&a[i+1].h);\n            a[i+1].x1=a[i].x1; a[i+1].x2=a[i].x2;\n            a[i].type=1;a[i+1].type=-1;\n            x[i]=a[i].x1;x[i+1]=a[i].x2;\n        }\n        sort(a+1,a+2*n+1);\n\/\/        for (int i=1;i<=2*n;i++) cout<<a[i].x1<<' '<<a[i].x2<<' '<<a[i].h<<' '<<a[i].type<<endl;\n\n        sort(x+1,x+2*n+1);\n        size=unique(x+1,x+2*n+1)-(x+1);\n\/\/        for (int i=1;i<=size;i++) cout<<x[i]<<' ';cout<<endl;\n\n        for (int i=1;i<=size;i++) hpos[x[i]]=i;\n\n        t.fillchar(size);\n\/*        for (int i=1;i<=t.M*2;i++) cout<<len[i]<<' ';\n        cout<<endl;\n*\/        \/*\n        t.insert(1,3,1);t.print();\n        t.insert(2,4,2);\n        cout<<t.find(1,3);\n        cout<<endl;\n        t.print();\n        *\/\n    \/\/    t.insert(2,3,1);\n        \/*\n        t.insert(2,3,1);\n        t.print();\n        t.insert(3,4,1);\n        t.print();\n        t.insert(2,3,-1);\n        t.print();\n\n        *\/\n\n        double ans=0;a[0].h=a[1].h;\n        for (int i=1;i<=2*n;i++)\n        {\n            ans+=(a[i].h-a[i-1].h)*t.sum[1];\n            t.insert(hpos[a[i].x1]+1,hpos[a[i].x2],a[i].type);\n\/*            t.print();\n            cout<<hpos[a[i].x1]+1<<' '<<hpos[a[i].x2]<<endl;\n            cout<<t.sum[1]<<endl;\n            cout<<ans<<endl;\n*\/        }\n        printf("Test case #%dnTotal explored area: %.2lfnn",tt,ans);\n\n\n    }\n    return 0;\n}<\/pre>\n
\n\u4e0a\u8ff0\u7a0b\u5e8f\u6548\u7387\u8f83\u6162(m(logm)^2) ,m\u4e3a\u8fb9\u6570<\/p>\n

\n<\/span><\/p>\n
\u6211\u4eec\u8003\u8651\u5230\uff0c\u6bcf\u6b21\u4e0a\u4f20\u5b9e\u5728\u592a\u8017\u65f6\u4e86\u3002<\/span><\/p>\n
\u4ed4\u7ec6\u89c2\u5bdf\u65b9\u7a0b\uff0c\u53d1\u73b0\u6bcf\u6b21\u4fee\u6539\u7684\u70b9\u4e00\u5b9a\u662f\u4ece\u53f6\u7ed3\u70b9\u5230\u6839\u8282\u70b9\u7684\u8def\u4e0a\u7684\u7ed3\u70b9\u7684\u5144\u5f1f\uff08\u4e0d\u5305\u62ec\u8def\u4e0a\uff09<\/span><\/p>\n
\u56e0\u6b64\u6bcf\u6b21\u88ab\u5f71\u54cd\u7684\u4e00\u5b9a\u662f\u8def\u4e0a\u7684\u7ed3\u70b9\u3002<\/span><\/p>\n
\u6545\u6211\u4eec\u6bcf\u6b21\u53ea\u66f4\u65b0\u7ed3\u70b9\u7684值\uff0c\u6700\u540e\u76f4\u63a5\u7531\u6839\u8282\u70b9\u5411\u4e0a\u9012\u5f52\uff0c\u5f97\u5230\u7a0b\u5e8f2-\u6548\u7387\u4e3aO(mlogm) \uff1a<\/span><\/p>\n

\n<\/span><\/p>\n
<\/span><\/p>\n
#include<cstdio>\n#include<cstring>\n#include<cstdlib>\n#include<cmath>\n#include<cctype>\n#include<iostream>\n#include<functional>\n#include<algorithm>\n#include<map>\nusing namespace std;\n#define MAXN (2000+10)\n#define MAXT (1000*2*10)\n#define Lson (x<<1)\n#define Rson ((x<<1)^1)\nint tt,n,size;\ndouble x[MAXN];\nstruct SegMent\n{\n    double x1,x2,h;\n    int type;\n    SegMent(){}\n    SegMent(double _x1,double _x2,double _h,int _type):x1(_x1),x2(_x2),h(_h),type(_type){}\n    friend bool operator<(const SegMent a,const SegMent b){return a.h<b.h;    }\n}a[MAXN];\nmap<double , int>  hpos;\ndouble len[MAXT];\nstruct SegMentTree\n{\n    int n,M,cnt[MAXT];\n    double sum[MAXT];\n    int mark[MAXT];\n    void fillchar(int _n)\n    {\n        n=_n;\n        memset(cnt,0,sizeof(cnt));\n        memset(sum,0,sizeof(sum));\n        memset(mark,0,sizeof(mark));\n        M=1;while (M-2<n) M<<=1;\n        x[0]=0;memset(len,0.0,sizeof(len));\n        for (int i=M+1;i<=M+size;i++) len[i]=x[i-M]-x[i-M-1];\n        for (int i=M-1;i>0;i--) len[i]=len[i<<1]+len[(i<<1)^1];\n    }\n    void pushup(int x)\n    {\n        sum[x]=cnt[x]?len[x]:(x>=M?0:sum[Lson]+sum[Rson]);\n    }\n    void update(int x)\n    {\n        for (;x;x>>=1)\n        {\n            pushup(x);\n        }\n    }\n\n    void insert(int l,int r,int c)\n    {\n        int ll=l-1+M,rr=r+1+M;\n        for (l=l-1+M,r=r+1+M;l^r^1;l>>=1,r>>=1)\n        {\n            if (~l&1) {cnt[l+1]+=c;pushup(l+1);} \/*\u6539\u53d8sum\u7684\u503c *\/\n            if (r&1) {cnt[r-1]+=c;pushup(r-1);}\n        }\n        update(ll);update(rr);\n    }\n}t;\n\nint main()\n{\n\/\/    freopen("Hdu1542.in","r",stdin);\n    tt=0;\n    while (scanf("%d",&n)!=EOF)\n    {\n        tt++;\n        if (!n) break;\n        for (int i=1;i<=2*n;i+=2)\n        {\n\t\t\tdouble x1,y1,x2,y2;\n            scanf("%lf%lf%lf%lf",&x1,&y1,&x2,&y2);\n            x[i]=x1;x[i+1]=x2;\n            a[i]=SegMent(x1,x2,y1,1);\n            a[i+1]=SegMent(x1,x2,y2,-1);\n        }\n\n        sort(a+1,a+2*n+1);\n        sort(x+1,x+2*n+1);\n        size=unique(x+1,x+2*n+1)-(x+1);\n        for (int i=1;i<=size;i++) hpos[x[i]]=i;\n        t.fillchar(size);\n\n\n        double ans=0;a[0].h=a[1].h;\n        for (int i=1;i<=2*n;i++)\n        {\n            ans+=(a[i].h-a[i-1].h)*t.sum[1];\n            t.insert(hpos[a[i].x1]+1,hpos[a[i].x2],a[i].type);\n        }\n        printf("Test case #%dnTotal explored area: %.2lfnn",tt,ans);\n\n\n    }\n    return 0;\n}<\/pre>\n<\/p>\n

\n<\/span><\/p>\n

\n<\/span><\/p>\n

\n<\/span><\/p>\n

\n<\/span><\/p>\n
<\/p>\n","protected":false},"excerpt":{"rendered":"
Atlantis Problem Description \u5df2\u77e5Atlantis\u7684\u5730\u56fe\u7531\u8bb8\u591a\u77e9\u5f62\u6784\u6210\uff0c\u6c42\u5b83\u4eec\u7684\u9762 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_coblocks_attr":"","_coblocks_dimensions":"","_coblocks_responsive_height":"","_coblocks_accordion_ie_support":"","footnotes":""},"categories":[3],"tags":[52,77],"class_list":["post-289","post","type-post","status-publish","format-standard","hentry","category-defaultcategory","tag-the_zkw_segment_tree","tag-scan_line"],"yoast_head":"\nHDU 1542(\u77e9\u5f62\u9762\u79ef\u5e76\uff09 - nike0good<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/nike0good.com\/?p=289\" \/>\n<meta property=\"og:locale\" content=\"zh_CN\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"HDU 1542(\u77e9\u5f62\u9762\u79ef\u5e76\uff09 - 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