{"id":358,"date":"2013-03-22T16:13:00","date_gmt":"2013-03-22T08:13:00","guid":{"rendered":"http:\/\/nike0good.jp1.rpvhost.net\/262"},"modified":"2013-03-22T16:13:00","modified_gmt":"2013-03-22T08:13:00","slug":"cf_23e__-_backpack_merger_tree-tree","status":"publish","type":"post","link":"https:\/\/nike0good.com\/?p=358","title":{"rendered":"CF 23E(Tree-\u6811-\u80cc\u5305\u5408\u5e76)"},"content":{"rendered":"<p>Problem 2 \u6811(tree.cpp\/c\/pas)<\/p>\n<p>\u3010\u9898\u76ee\u63cf\u8ff0\u3011<\/p>\n<p>L\u53d1\u660e\u4e86\u4e00\u79cd\u4e0e\u6811\u6709\u5173\u7684\u6e38\u620f\uff08\u53cb\u60c5\u63d0\u9192\uff1a\u6811\u662f\u4e00\u4e2a\u6ca1\u6709\u73af\u7684\u8fde\u901a\u56fe\uff09\uff1a\u4ed6\u4ece\u6811\u4e2d\u5220\u9664\u4efb\u610f\u6570\u91cf\uff08\u53ef\u4ee5\u4e3a0\uff09\u7684\u8fb9\uff0c\u8ba1\u7b97\u5220\u9664\u540e\u6240\u6709\u8fde\u901a\u5757\u5927\u5c0f\u7684\u4e58\u79ef\uff0cL\u5c06\u5f97\u5230\u8fd9\u4e48\u591a\u7684\u5206\u6570\u3002\u4f60\u7684\u4efb\u52a1\u5c31\u662f\u5bf9\u4e8e\u4e00\u9897\u7ed9\u5b9a\u7684\u6811\uff0c\u6c42\u51faL\u80fd\u5f97\u5230\u7684\u6700\u5927\u5206\u6570\u3002\n<\/p>\n<p>\u3010\u8f93\u5165&#26684;\u5f0f\u3011<\/p>\n<p>\u7b2c\u4e00\u884c\u4e00\u4e2a\u6574\u6570n\uff0c\u8868\u793a\u6811\u7684\u8282\u70b9\u4e2a\u6570\u3002<br \/>\n\u3000\u3000\u63a5\u4e0b\u6765n-1\u884c\uff0c\u6bcf\u884c\u4e24\u4e2a\u6574\u6570a[i],b[i](1&lt;=a[i],b[i]&lt;=n)\uff0c\u8868\u793aa[i]\u4e0eb[i]\u4e4b\u95f4\u8fde\u8fb9\u3002<br \/>\n\u3000\u3000\u4fdd\u8bc1\u8f93\u5165\u7684\u56fe\u662f\u4e00\u68f5\u6811\u3002 <\/p>\n<p>\u3010\u8f93\u51fa&#26684;\u5f0f\u3011<\/p>\n<p>\u8f93\u51fa\u4e00\u4e2a\u6574\u6570\uff0c\u8868\u793aL\u80fd\u5f97\u5230\u7684\u6700\u5927\u5206\u6570\u3002<\/p>\n<p>&nbsp;\u3010\u6837\u4f8b\u8f93\u5165\u3011<\/p>\n<p>\u6837\u4f8b1\uff1a<br \/>\n5<br \/>\n1 2<br \/>\n2 3<br \/>\n3 4<br \/>\n4 5<br \/>\n\u6837\u4f8b2\uff1a<br \/>\n8<br \/>\n1 2<br \/>\n1 3<br \/>\n2 4<br \/>\n2 5<br \/>\n3 6<br \/>\n3 7<br \/>\n6 8<br \/>\n\u6837\u4f8b3\uff1a<br \/>\n3<br \/>\n1 2<br \/>\n1 3 <\/p>\n<p>\u3010\u6837\u4f8b\u8f93\u51fa\u3011<\/p>\n<p>\u6837\u4f8b1\uff1a<br \/>\n6<br \/>\n\u6837\u4f8b2\uff1a<br \/>\n18<br \/>\n\u6837\u4f8b3\uff1a<br \/>\n3 <\/p>\n<p>\u3010\u6570\u636e\u8303\u56f4\u3011<\/p>\n<p>&nbsp;&nbsp;&nbsp; \u5bf9\u4e8e10%\u7684\u6570\u636e\uff0c1&lt;=n&lt;=5\uff1b<br \/>\n\u3000\u3000\u5bf9\u4e8e30%\u7684\u6570\u636e\uff0c1&lt;=n&lt;=100\uff1b<br \/>\n\u3000\u3000\u53e6\u670930%\u7684\u6570\u636e\uff0c\u4fdd\u8bc1\u6570\u636e\u662f\u4e00\u6761\u94fe\u3002<br \/>\n\u3000\u3000\u5bf9\u4e8e100%\u7684\u6570\u636e\uff0c1&lt;=n&lt;=700\uff1b<\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"font-size:14px\">\u6811\u4e0a\u80cc\u5305<\/span><\/p>\n<p><span style=\"font-size:14px\">f[i][j]\u8868\u793ai\u7684\u7236\u4eb2\u7684\u8fde\u901a\u5757\u5728\u5b50\u6811i\u4e2d\u6709j\u4e2a\u7684\u6700\u5927\u7684\u6700\u5927&#20540;\u3002<\/span><\/p>\n<p><span style=\"font-size:14px\">\u4e8e\u662f\u8fd9\u5c31\u662f\u6811\u5f62Dp&#43;\u80cc\u5305\u5408\u5e76\u4e86\u3001<\/span><\/p>\n<p><span style=\"font-size:14px\">\u80cc\u5305\u5408\u5e762\u4e2a\u5148\u5408\u5e76\uff0c\u518d\u4e0e\u7b2c\u4e09\u4e2a\u2026\u2026<\/span><\/p>\n<p><span style=\"font-size:14px\"><\/span><\/p>\n<pre name=\"code\" class=\"cpp\">#include&lt;cstdio&gt;\n#include&lt;cstring&gt;\n#include&lt;algorithm&gt;\n#include&lt;functional&gt;\n#include&lt;iostream&gt;\n#include&lt;cstdlib&gt;\n#include&lt;cmath&gt;\nusing namespace std;\n#define MAXN (700+10)\n#define ll long long\n#define F (100000000)\nint n,edge[MAXN*2],pre[MAXN],next[MAXN*2],size=0,son[MAXN];\nstruct bign\n{\n\tll a[40];\n\tbign(){memset(a,0,sizeof(a));a[0]=1;}\n\tbign(int x){memset(a,0,sizeof(a)); a[0]=1;a[1]=x;\t}\n\tll&amp; operator[](const int i){return a[i];\t}\n\tfriend bign operator*(bign a,bign b)\n\t{\n\t\tbign c;\n\t\tfor (int i=1;i&lt;=a[0];i++)\n\t\t\tfor (int j=1;j&lt;=b[0];j++)\n\t\t\t{\n\t\t\t\tc[i+j-1]+=a[i]*b[j];\n\t\t\t\tif (c[i+j-1]&gt;F)\n\t\t\t\t{\n\t\t\t\t\tc[i+j]+=c[i+j-1]\/F;\n\t\t\t\t\tc[i+j-1]%=F;\n\t\t\t\t}\n\t\t\t}\n\t\tc[0]=min(a[0]+b[0],(long long)39);while (!c[c[0]]&amp;&amp;c[0]&gt;1) c[0]--;\n\t\treturn c;\n\t}\n\tfriend bool operator&gt;(bign a,bign b)\n\t{\n\t\tif (a[0]!=b[0]) return a[0]&gt;b[0];\n\t\tfor (int i=a[0],j=b[0];i&gt;0;i--,j--) if (a[i]!=b[j]) return a[i]&gt;b[j];\n\t\treturn false;\n\t}\n\tvoid print()\n\t{\n\t\tprintf(&quot;%I64d&quot;,a[a[0]]);\n\t\tfor (int i=a[0]-1;i;i--)\n\t\t{\n\t\t\tprintf(&quot;%.8I64d&quot;,a[i]);\n\t\t}\n\t}\n}f[MAXN][MAXN];\nbign max(bign a,bign b)\n{\n\tif (a&gt;b) return a;\n\treturn b;\n}\nvoid addedge(int u,int v)\n{\n\tedge[++size]=v;\n\tnext[size]=pre[u];\n\tpre[u]=size;\n}\nvoid dfs(int x,int father)\n{\n\tson[x]=1;\/\/f[x][1]=1;\n\tf[x][1]=1;\n\tfor (int p=pre[x];p;p=next[p])\n\t{\n\t\tint &amp;v=edge[p];\n\t\tif (v!=father)\n\t\t{\n\t\t\tdfs(v,x);\n\t\t\t\/*\n\t\t\tfor (int i=son[x]+son[v];i&gt;0;i--)\n\t\t\t{\n\t\t\t\tif (i&lt;son[x]) f[x][i]=f[x][i]*son[v];\n\t\t\t\tfor (int k=son[v];k&gt;=0;k--)\n\t\t\t\t\tif (i-k-1&gt;=0) f[x][i]=max(f[x][i],f[x][i-k-1]*f[v][k]);\n\n\t\t\t}\n\t\t\tson[x]+=son[v];\n\t\t\tbign maxv=son[v];\n\t\t\tfor (int k=0;k&lt;=son[v]-1;k++) maxv=max(maxv,f[v][k]*(k+1));\n\t\t\tf[x][0]=f[x][0]*maxv;\n\t\t\t*\/\n\t\t\tfor (int i=son[x];i;i--)\n\t\t\t\tfor (int j=son[v];j&gt;=0;j--)\n\t\t\t\t\tf[x][i+j]=max(f[x][i+j],f[x][i]*f[v][j]);\n\t\t\tson[x]+=son[v];\n\t\t}\n\t}\n\tf[x][0]=bign(son[x]);\n\tfor (int i=1;i&lt;=son[x];i++) f[x][0]=max(f[x][0],f[x][i]*bign(i));\n\n\n\n\n\treturn;\n}\nint main()\n{\n\/\/\tfreopen(&quot;tree.in&quot;,&quot;r&quot;,stdin);\n\/\/\tfreopen(&quot;tree.out&quot;,&quot;w&quot;,stdout);\n\tscanf(&quot;%d&quot;,&amp;n);\n\tmemset(pre,0,sizeof(pre));\n\tmemset(next,0,sizeof(next));\n\tfor (int i=1;i&lt;n;i++)\n\t{\n\t\tint u,v;\n\t\tscanf(&quot;%d%d&quot;,&amp;u,&amp;v);\n\t\taddedge(u,v);addedge(v,u);\n\t}\n\taddedge(n+1,1);\n\tdfs(n+1,0);\t\/\/n+1 is ans\n\t\/*\n\tfor (int i=1;i&lt;=n+1;i++)\n\t{\n\t\tfor (int j=0;j&lt;=son[i]-1;j++)\n\t\t{\n\t\t\tf[i][j].print();printf(&quot; &quot;);\n\t\t}\n\t\tprintf(&quot;n&quot;);\n\t}\n\t*\/\n\/\/\tf[n+1][1]=bign(123456789)*bign(234567899);\n\n\tf[1][0].print();\n\tprintf(&quot;n&quot;);\n\n\treturn 0;\n}<\/pre><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Problem 2 \u6811(tree.cpp\/c\/pas) \u3010\u9898\u76ee\u63cf\u8ff0\u3011 L\u53d1\u660e\u4e86\u4e00\u79cd\u4e0e\u6811\u6709\u5173\u7684\u6e38\u620f\uff08\u53cb\u60c5\u63d0\u9192\uff1a\u6811 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_coblocks_attr":"","_coblocks_dimensions":"","_coblocks_responsive_height":"","_coblocks_accordion_ie_support":"","footnotes":""},"categories":[3],"tags":[93,114],"class_list":["post-358","post","type-post","status-publish","format-standard","hentry","category-defaultcategory","tag-tree_dp","tag-knapsack_problem"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.5 - 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