{"id":557,"date":"2015-09-17T20:40:57","date_gmt":"2015-09-17T12:40:57","guid":{"rendered":"http:\/\/nike0good.jp1.rpvhost.net\/?p=509"},"modified":"2015-09-17T20:40:57","modified_gmt":"2015-09-17T12:40:57","slug":"codeforces-round-320-div-1-bayan-thanks-round-%e9%a2%98%e8%a7%a3","status":"publish","type":"post","link":"https:\/\/nike0good.com\/?p=557","title":{"rendered":"Codeforces Round #320 (Div. 1) [Bayan Thanks-Round] \u9898\u89e3"},"content":{"rendered":"<p>A.<\/p>\n<p>There is a polyline going through points&nbsp;(0,\u20090)\u2009\u2013\u2009(<i>x<\/i>,\u2009<i>x<\/i>)\u2009\u2013\u2009(2<i>x<\/i>,\u20090)\u2009\u2013\u2009(3<i>x<\/i>,\u2009<i>x<\/i>)\u2009\u2013\u2009(4<i>x<\/i>,\u20090)\u2009\u2013\u2009...\u2009-\u2009(2<i>kx<\/i>,\u20090)\u2009\u2013\u2009(2<i>kx<\/i>\u2009+\u2009<i>x<\/i>,\u2009<i>x<\/i>)\u2009\u2013\u2009....<\/p>\n<p>We know that the polyline passes through the point&nbsp;(<i>a<\/i>,\u2009<i>b<\/i>). Find minimum positive value&nbsp;<i>x<\/i>&nbsp;such that it is true or determine that there is no such&nbsp;<i>x<\/i>.<\/p>\n<p>\u9898\u89e3\uff1a\u6240\u6709\u7ebf\u7684\u659c\u7387\u5747\u4e3a\\(k=\\pm1\\)<\/p>\n<p><code lang=\"cpp[lines-notools]\">#include<cstdio><br \/>\n#include<cstring><br \/>\n#include<cstdlib><br \/>\n#include<algorithm><br \/>\n#include<functional><br \/>\n#include<iostream><br \/>\n#include<cmath><br \/>\n#include<cctype><br \/>\n#include<ctime><br \/>\nusing namespace std;<br \/>\n#define For(i,n) for(int i=1;i< =n;i++)\n#define Fork(i,k,n) for(int i=k;i<=n;i++)\n#define Rep(i,n) for(int i=0;i<n;i++)\n#define ForD(i,n) for(int i=n;i;i--)\n#define RepD(i,n) for(int i=n;i>=0;i--)<br \/>\n#define Forp(x) for(int p=pre[x];p;p=next[p])<br \/>\n#define Forpiter(x) for(int &p=iter[x];p;p=next[p])<br \/>\n#define Lson (x< &lt;1)\n#define Rson ((x<&lt;1)+1)\n#define MEM(a) memset(a,0,sizeof(a));\n#define MEMI(a) memset(a,127,sizeof(a));\n#define MEMi(a) memset(a,128,sizeof(a));\n#define INF (2139062143)\n#define eps (1e-10)\n#define F (100000007)\ntypedef long long ll;\ntypedef double ld;\nll mul(ll a,ll b){return (a*b)%F;}\nll add(ll a,ll b){return (a+b)%F;}\nll sub(ll a,ll b){return (a-b+llabs(a-b)\/F*F+F)%F;}\nvoid upd(ll &a,ll b){a=(a%F+b%F)%F;}\nld a,b;\nint main()\n{\n\/\/ freopen(\"A.in\",\"r\",stdin);\n\/\/ freopen(\".out\",\"w\",stdout);\n\n cin>>a>>b;<br \/>\n if (a<b ) {\n cout<<\"-1\\n\";return 0;\n }\n ld ans=1e70;\n\n ld m=floor((a+b)\/b\/2)*2;\n ans=min(ans,(a+b)\/floor(m));\n\n m=floor((a-b)\/b\/2)*2;\n ans=min(ans,(a-b)\/floor(m));\n printf(\"%.12lf\\n\",ans);\n return 0;\n}<\/code><\/p>\n<p>B.\"Or\" Game<\/p>\n<p>\u5df2\u77e5n\u4e2a\u6570\uff0c\u6267\u884ck\u6b21\u64cd\u4f5c\uff1a\u5c06\u4efb\u610f\u4e00\u4e2a\u6570\u4e58x\uff0c\u6c42\u6700\u5927or\u548c<\/p>\n<p>(1\u2009&le;\u2009n\u2009&le;\u2009200\u2009000, 1\u2009&le;\u2009k\u2009&le;\u200910, 2\u2009&le;\u2009x\u2009&le;\u20098).<\/p>\n<p>\u89e3\u6cd5\uff1a\u7531\u4e8e \\(x\\geqslant2\\) \u6211\u4eec\u5e94\u8be5\u5c06\u4f4d\u6570\u6700\u5927\u7684\u90a3\u4e2a1\u632a\u5230\u5c3d\u53ef\u80fd\u9ad8\u4f4d\uff0c\u56e0\u6b64\uff0c\u5e94\u53cd\u590d\u4e58\u540c\u4e00\u4e2a\u6570<\/p>\n<p>\u7528\u7ebf\u6bb5\u6811\u9884\u5904\u7406\u533a\u95f4or\u548c\uff0c\u7136\u540e\u679a\u4e3e\u6267\u884c\u64cd\u4f5c\u7684\u6570\u5373\u53ef<\/p>\n<p><code lang=\"cpp[lines-notools]\">#include<cstdio><br \/>\n#include<cstring><br \/>\n#include<cstdlib><br \/>\n#include<algorithm><br \/>\n#include<functional><br \/>\n#include<iostream><br \/>\n#include<cmath><br \/>\n#include<cctype><br \/>\n#include<ctime><br \/>\nusing namespace std;<br \/>\n#define For(i,n) for(int i=1;i< =n;i++)\n#define Fork(i,k,n) for(int i=k;i<=n;i++)\n#define Rep(i,n) for(int i=0;i<n;i++)\n#define ForD(i,n) for(int i=n;i;i--)\n#define RepD(i,n) for(int i=n;i>=0;i--)<br \/>\n#define Forp(x) for(int p=pre[x];p;p=next[p])<br \/>\n#define Forpiter(x) for(int &p=iter[x];p;p=next[p])<br \/>\n#define Lson (x< &lt;1)\n#define Rson ((x<&lt;1)+1)\n#define MEM(a) memset(a,0,sizeof(a));\n#define MEMI(a) memset(a,127,sizeof(a));\n#define MEMi(a) memset(a,128,sizeof(a));\n#define INF (2139062143)\n#define F (100000007)\n#define MAXN (200000+10)\ntypedef long long ll;\nll mul(ll a,ll b){return (a*b)%F;}\nll add(ll a,ll b){return (a+b)%F;}\nll sub(ll a,ll b){return (a-b+llabs(a-b)\/F*F+F)%F;}\nvoid upd(ll &a,ll b){a=(a%F+b%F)%F;}\nll a[MAXN],x;\nint n,k;\nclass SegmentTree\n{\n    ll minv[MAXN*4];\n    int n;\npublic:\n    SegmentTree(){MEM(minv) }\n    SegmentTree(int _n):n(_n){ MEM(minv) }\n    void mem(int _n)\n    {\n        n=_n;\n        MEM(minv)\n    }\n    void build(int x,int L,int R)\n    {\n        int M=(L+R)>>1;<br \/>\n        if (L==R) {minv[x]=a[L];return;}<br \/>\n        else<br \/>\n        {<br \/>\n            if (L< =M) build(Lson,L,M);\n            if (M<r) build(Rson,M+1,R);\n        }\n        minv[x]=minv[Lson]|minv[Rson];\n    }\n    int ql,qr;\n    ll query_min(int ql,int qr)\n    {\n        this->ql=ql,this->qr=qr;<br \/>\n        if (ql>qr) return 0;<br \/>\n        return _query_min(1,1,n);<br \/>\n    }<\/p>\n<p>    ll _query_min(int x,int L,int R)<br \/>\n    {<br \/>\n        if (ql< =L&&R<=qr) return minv[x];\n        ll ans=0,M=(L+R)>>1;<br \/>\n        if (ql< =M) ans|=_query_min(Lson,L,M);\n        if (M< qr) ans|=_query_min(Rson,M+1,R);\n        return ans;\n    }\n\n}S;\nint main()\n{\n\/\/ freopen(\"B.in\",\"r\",stdin);\n\/\/ freopen(\".out\",\"w\",stdout);\n\n cin>>n>>k>>x;<br \/>\n For(i,n) scanf(\"%I64d\",&a[i]);<br \/>\n sort(a+1,a+1+n);<\/p>\n<p> S.mem(n);<br \/>\n S.build(1,1,n);<\/p>\n<p> ll e=0;<br \/>\n For(i,n)<br \/>\n {<br \/>\n ll ans=0;<br \/>\n ans|=S.query_min(1,i-1);<br \/>\n ans|=S.query_min(i+1,n);<\/p>\n<p> ll t=a[i];<br \/>\n For(i,k) t*=x;<br \/>\n ans|=t;<br \/>\n e=max(e,ans);<br \/>\n }<br \/>\n cout< <e<<endl;\n\n return 0;\n}\n<\/code><\/p>\n<p>&nbsp;C .\u5df2\u77e5\u5e8f\u5217<i>a<\/i>1,\u2009<i>a<\/i>2,\u2009...,\u2009<i>a<\/i><i>n<\/i>&nbsp;(|<i>a<\/i><i>i<\/i>|\u2009&le;\u200910\u2009000,1\u2009&le;\u2009<i>n<\/i>\u2009&le;\u2009200\u2009000). \u6c42x,<\/p>\n<p>\u4f7f\u5e8f\u5217<i>a<\/i>1\u2009-\u2009<i>x<\/i>,\u2009<i>a<\/i>2\u2009-\u2009<i>x<\/i>,\u2009...,\u2009<i>a<\/i><i>n<\/i>\u2009-\u2009<i>x&nbsp;<\/i>\u7684\u5b50\u6bb5\u548c\u7684\u7edd\u5bf9\u503c\u6700\u5c0f.<\/p>\n<p>\u89e3\u6cd5\uff1a\u4e8c\u5206x\uff0c\u5982\u679c\u6700\u5927\u5b50\u6bb5\u548c\u4e0e\u6700\u5c0f\u5b50\u6bb5\u548c\u5e73\u5747\u503c\\(\\geqslant 0\\),\u5219\u8bf4\u660ex\u592a\u5927.<\/p>\n<p><code lang=\"cpp[lines-notools]\">#include<cstdio><br \/>\n#include<cstring><br \/>\n#include<cstdlib><br \/>\n#include<algorithm><br \/>\n#include<functional><br \/>\n#include<iostream><br \/>\n#include<cmath><br \/>\n#include<cctype><br \/>\n#include<ctime><br \/>\nusing namespace std;<br \/>\n#define For(i,n) for(int i=1;i< =n;i++)\n#define Fork(i,k,n) for(int i=k;i<=n;i++)\n#define Rep(i,n) for(int i=0;i<n;i++)\n#define ForD(i,n) for(int i=n;i;i--)\n#define RepD(i,n) for(int i=n;i>=0;i--)<br \/>\n#define Forp(x) for(int p=pre[x];p;p=next[p])<br \/>\n#define Forpiter(x) for(int &p=iter[x];p;p=next[p])<br \/>\n#define Lson (x< &lt;1)\n#define Rson ((x<&lt;1)+1)\n#define MEM(a) memset(a,0,sizeof(a));\n#define MEMI(a) memset(a,127,sizeof(a));\n#define MEMi(a) memset(a,128,sizeof(a));\n#define INF (2139062143)\n#define F (100000007)\n#define eps (1e-8)\n#define MAXN (200000+10)\ntypedef long long ll;\nll mul(ll a,ll b){return (a*b)%F;}\nll add(ll a,ll b){return (a+b)%F;}\nll sub(ll a,ll b){return (a-b+llabs(a-b)\/F*F+F)%F;}\nvoid upd(ll &a,ll b){a=(a%F+b%F)%F;}\nint n;\ndouble a[MAXN];\ndouble ans;\nbool check(double x)\n{\n double mins=a[1]-x,maxs=a[1]-x;\n\n double t1=0,t2=0;\n For(i,n) {\n t1=max(t1+a[i]-x,a[i]-x);\n maxs=max(maxs,t1);\n t2=min(t2+a[i]-x,a[i]-x);\n mins=min(mins,t2);\n }\n ans=maxs;\n return (mins+maxs)\/2 &lt;0;\n}\nint main()\n{\n\/\/ freopen(\"c.in\",\"r\",stdin);\n\/\/ freopen(\".out\",\"w\",stdout);\n\n cin>>n;<br \/>\n For(i,n) scanf(\"%lf\",&a[i]);<\/p>\n<p> double l=-2000000000,r=2000000000;<br \/>\n int k=150;<br \/>\n while (k--)<br \/>\n {<br \/>\n double m=(l+r)\/2;<br \/>\n if (check(m)) r=m;<br \/>\n else l=m;<br \/>\n }<br \/>\n check((l+r)\/2);<br \/>\n printf(\"%.7lf\\n\",ans);<br \/>\n return 0;<br \/>\n}<!--DVFMTSC--><br \/>\n<\/ctime><\/cctype><\/cmath><\/iostream><\/functional><\/algorithm><\/cstdlib><\/cstring><\/cstdio><\/code><\/ctime><\/cctype><\/cmath><\/iostream><\/functional><\/algorithm><\/cstdlib><\/cstring><\/cstdio><\/code><\/b><\/ctime><\/cctype><\/cmath><\/iostream><\/functional><\/algorithm><\/cstdlib><\/cstring><\/cstdio><\/code><\/p>\n","protected":false},"excerpt":{"rendered":"<p>A. There is a polyline going through points&nbsp;(0,\u20090) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_coblocks_attr":"","_coblocks_dimensions":"","_coblocks_responsive_height":"","_coblocks_accordion_ie_support":"","footnotes":""},"categories":[12],"tags":[],"class_list":["post-557","post","type-post","status-publish","format-standard","hentry","category-algorithm"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v28.0 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Codeforces Round #320 (Div. 1) [Bayan Thanks-Round] \u9898\u89e3 - nike0good<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/nike0good.com\/?p=557\" \/>\n<meta property=\"og:locale\" content=\"zh_CN\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Codeforces Round #320 (Div. 1) [Bayan Thanks-Round] \u9898\u89e3 - nike0good\" \/>\n<meta property=\"og:description\" content=\"A. 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